9t^2-12t-5=0

Solution for 9t^2-12t-5=0 equation:

9t^2-12t-5=0

a = 9; b = -12; c = -5;
Δ = b2-4ac
Δ = -122-4·9·(-5)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-18}{2*9}=\frac{-6}{18}
=-1/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+18}{2*9}=\frac{30}{18}
=1+2/3
$